How do you evaluate $({cos}^{3} (\frac{π}{6})) (sin (\frac{π}{4}))$ $(cos^3 (pi/6))(sin (pi/4))$ ?

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How do you evaluate $({cos}^{3} (\frac{π}{6})) (sin (\frac{π}{4}))$ $(cos^3 (pi/6))(sin (pi/4))$ ?

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Answer 1 · 2016-03-26T11:55:10

from trigonometric table we know
$cos (\frac{π}{6}) = \frac{\sqrt{3}}{2} and sin (\frac{π}{4}) = \frac{1}{\sqrt{2}}$ $cos (pi/6)=sqrt3/2 and sin(pi/4)=1/sqrt2$
putting these values we get
given expression
$= {(\frac{\sqrt{3}}{2})}^{3} \times \frac{1}{\sqrt{2}} = \frac{3 \sqrt{3}}{8 \sqrt{2}}$ $=(sqrt3/2)^3xx1/sqrt2=(3sqrt3)/(8sqrt2)$

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How do you evaluate $({cos}^{3} (\frac{π}{6})) (sin (\frac{π}{4}))$ $(cos^3 (pi/6))(sin (pi/4))$ ?

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