Question

How do you evaluate `cos(arctan sqrt 3 + arc cot sqrt3)`?

Answer 1

0

Explanation:

If `a = arc tan x, and b + arc cot x`, the principal values of a and b are complementary and differ by `pi/2`. The general values differ by an odd multiple of `pi/2`.

Anyway, cos ( arc tan x + arc cot x ) = cos ( odd multiple of `pi/2` ) = 0.
Here, x = `sqrt 3`..