How do you evaluate $cos (\frac{π}{6} + \frac{π}{3})$ $cos (pi/6 + pi/3)$ ?

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How do you evaluate $cos (\frac{π}{6} + \frac{π}{3})$ $cos (pi/6 + pi/3)$ ?

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Answer 1 · 2018-05-23T12:51:34

$0$ $0$

Explanation:

$cos (\frac{π}{6} + \frac{π}{3})$ $cos(pi/6+pi/3)$

$= cos (\frac{π}{6} + \frac{2 π}{6}) = cos (\frac{3 π}{6}) = cos (\frac{π}{2}) = 0$ $=cos(pi/6+(2pi)/6)=cos((3pi)/6)=cos(pi/2)=0$

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How do you evaluate $cos (\frac{π}{6} + \frac{π}{3})$ $cos (pi/6 + pi/3)$ ?

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How do you evaluate $cos (\frac{π}{6} + \frac{π}{3})$ $cos (pi/6 + pi/3)$ ?