How do you evaluate $cos(tan^-1(sqrt3/3 + sin^-1 (1/2)))$ ?

Question

2817 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-09T15:25:49

$0.672355$ , nearly

The given expression is

$cos(tan^(-1)(1/sqrt3+pi/6))$

$=cos(tan^(-1)(tan^(-1)(1.10095))$ , nearly

$=cos(47.751^o)$ , nearly

$=0.672355$ , nearly.

How do you evaluate cos(tan^-1(sqrt3/3 + sin^-1 (1/2)))cos(tan^-1(sqrt3/3 + sin^-1 (1/2)))?