How do you evaluate $cot^-1(1/sqrt3)$ without a calculator?

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Answer 1 · 2017-05-16T14:46:07

$"arc"cot(1/sqrt3)=1/3pi$

Let $theta="arc"cot(1/sqrt3)$

$cottheta=1/sqrt3$

$tantheta=sqrt3$

This is one of the angles you should know and works out to be $1/3pi$

How do you evaluate cot^-1(1/sqrt3)cot^-1(1/sqrt3) without a calculator?