How do you evaluate "cot270#?

1 Answer

Nov 4, 2015

We have that

$cos (270^{o}) = cot (180^{o} + 90^{o}) = cot (90^{o}) = \frac{cos 90}{sin 90} = \frac{0}{1} = 0$ $cos(270^o)=cot(180^o + 90^o)=cot(90^o)=cos90/sin90=0/1=0$

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How do you evaluate "cot270#?

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