How do you evaluate $f (- 1)$ $f(-1)$ given the function $f (t) = \frac{1}{2} t^{2} + 4$ $f(t)=\frac{1}{2} t^2+4$ ?

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How do you evaluate $f (- 1)$ $f(-1)$ given the function $f (t) = \frac{1}{2} t^{2} + 4$ $f(t)=\frac{1}{2} t^2+4$ ?

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Answer 1 · 2018-05-13T20:42:20

$f (- 1) = \frac{9}{2}$ $f(-1)=9/2$

Explanation:

$to evaluate f (- 1) substitute t = - 1 into f (t)$ $"to evaluate "f(-1)" substitute "t=-1" into "f(t)$

$\Rightarrow f (- 1) = \frac{1}{2} {(- 1)}^{2} + 4 = \frac{1}{2} + 4 = 4 \frac{1}{2} = \frac{9}{2}$ $rArrf(color(red)(-1))=1/2(color(red)(-1))^2+4=1/2+4=4 1/2=9/2$

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How do you evaluate $f (- 1)$ $f(-1)$ given the function $f (t) = \frac{1}{2} t^{2} + 4$ $f(t)=\frac{1}{2} t^2+4$ ?

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How do you evaluate $f (- 1)$ $f(-1)$ given the function $f (t) = \frac{1}{2} t^{2} + 4$ $f(t)=\frac{1}{2} t^2+4$ ?