How do you evaluate $g(x)=-lnx$ for $x=1/2$ ?

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Answer 1 · 2017-05-16T11:28:21

For $x=1/2; g(x) ~~0.693147$ ;#

$x= 1/2 , g(x) = - ln(x) :. g(1/2) = -ln(1/2) = -[ln(1)-ln(2)] ~~ - [0-0.693147) ~~0.693147$
For $x=1/2; g(x) ~~0.693147$ ;#
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How do you evaluate g(x)=-lnxg(x)=-lnx for x=1/2x=1/2?