How do you evaluate $h (x) = - \frac{5}{3} | x | + 6$ $h(x)= -5/3absx + 6$ for x=-2?

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How do you evaluate $h (x) = - \frac{5}{3} | x | + 6$ $h(x)= -5/3absx + 6$ for x=-2?

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Answer 1 · 2017-07-29T04:31:07

$h (x) = \frac{13}{3}$ $h(x)= 13/3$ at x = -2

Explanation:

$h (x)$ $h(x)$ is just a way of writing "a function (call it h) in x", meaning whatever is on the other side of the equation. Given a particular value (-2) you just put it into the equation and solve it.
$h (x) = - (\frac{5}{3}) | x | + 6$ $h(x)=−(5/3)|x|+6$
$h (x) = - (\frac{5}{3}) | - 2 | + 6$ $h(x)=−(5/3)|-2|+6$ ; $h (x) = - (\frac{5}{3}) \cdot 2 + 6$ $h(x)=−(5/3)*2+6$
$h (x) = - (\frac{10}{6}) + 6$ $h(x)=−(10/6)+6$ ; $h (x) = - (\frac{10}{6}) + \frac{36}{6}$ $h(x)=−(10/6)+36/6$
$h (x) = \frac{26}{6}$ $h(x)= 26/6$ ; $h (x) = \frac{13}{3}$ $h(x)= 13/3$ or 4.33

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How do you evaluate $h (x) = - \frac{5}{3} | x | + 6$ $h(x)= -5/3absx + 6$ for x=-2?

1 Answer

Explanation:

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