How do you evaluate #k(-6)# given #k(n)=n+2#?

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Answer 1 · 2016-08-13T21:00:00

#k(-6)=-4#

#k(n)=n+2#

or

#k(-6)=-6+2#

or
#k(-6)=-4#

Answer 2 · 2016-08-13T21:00:54

#k(-6) = -4#

All the fancy notation just means that #n = -6#
Replace #n# by the value #-6#

#k(color(red)n) = color(red)n+2#

#:.k(color(red)(-6)) = color(red)(-6)+2 = -4#