How do you evaluate #lne^45#?

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Answer 1 · 2016-11-17T17:56:43

45

two of the laws of logs are:

1) #log_ax^n=nlog_ax, AAainRR#

2) # log_aa=1, AAainRR#

so #lne^45#

#=45lne#

#ln# is to base # e#

#:.=45#