How do you evaluate $lne^45$ ?

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Answer 1 · 2016-11-17T17:56:43

45

two of the laws of logs are:

1) $log_ax^n=nlog_ax, AAainRR$

2) $log_aa=1, AAainRR$

so $lne^45$

$=45lne$

$ln$ is to base $e$

$:.=45$