Question

How do you evaluate `lne^(-4x)`?

Answer 1

`-4x`

Explanation:

`ln e^(-4x)`=`log_e e^(-4x)`
The way I remember log relationships is
`2^3=8` and `log_2 8=3` are two ways of writing the same thing.
So if `log_e e^(-4x)` = n
Then `e^n=e^(-4x)`
And `n=-4x`

`log_e e^(-4x)= -4x`
Or `ln e^(-4x) =-4x`