How do you evaluate ${log}_{\frac{1}{2}} 32$ $log_(1/2) 32$ ?

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How do you evaluate ${log}_{\frac{1}{2}} 32$ $log_(1/2) 32$ ?

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Answer 1 · 2016-08-29T00:13:30

$- 5$ $-5$

Explanation:

${log}_{\frac{1}{2}} 32 = \frac{{log}_{e} 32}{{log}_{e} (\frac{1}{2})} = \frac{{log}_{e} 2^{5}}{- {log}_{e} 2} = - 5 \frac{{log}_{e} 2}{{log}_{e} 2} = - 5$ $log_(1/2) 32 = log_e 32/(log_e (1/2)) = log_e 2^5/(-log_e 2) = -5log_e 2/(log_e 2) = -5$

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How do you evaluate ${log}_{\frac{1}{2}} 32$ $log_(1/2) 32$ ?

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