How do you evaluate $log_2 1$ ?

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Answer 1 · 2016-07-21T10:47:28

$log_2 1=0$

From the definition of logarithm, if $a^m=b$ then $log_ab=m$ .

Now as for all values of $a$ , $a^0=1$ , hence $log_a1=0$

Hence $log_2 1=0$

How do you evaluate log_2 1log_2 1?