How do you evaluate $log_2 (1/16)$ ?

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Answer 1 · 2016-06-28T08:01:19

-4

let $z = log_2 (1/16)$

$\implies z = - log_2 (16)$

$\implies -z = log_2 (16)$

$= log_2 (2^4)$

$= 4 log_2 (2)$

$= 4*1 = 4$

$z = -4$

How do you evaluate log_2 (1/16)log_2 (1/16)?