How do you evaluate ${log}_{3} 1$ $log_3 1$ ?

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Answer 1 · 2016-08-15T20:25:53

I found that it is equal to zero:

You may use the definition of log:
${log}_{b} a = x$ $log_ba=x$
so that: $a = b^{x}$ $a=b^x$

we now need to find our $x$ $x$ in:
${log}_{3} (1) = x$ $log_3(1)=x$

using our definition we see that the only possible value for $x$ $x$ is zero because:
$1 = 3^{0}$ $1=3^0$

Answer 2 · 2016-08-15T21:24:26

${log}_{3} 1 = 0$ $log_3 1 = 0$

Written in log form, the question being asked is,"

"1 is which power of 3? " $3^{0} = 1$ $3^0 =1$

Or

"Using a base of 3, what index will give 1 as the answer?"
$3^{0} = 1$ $3^0 =1$

Log form and index form are interchangeable.

${log}_{3} 1 = x \Rightarrow 3^{x} = 1$ $log_3 1 = x " " rArr 3^x = 1$

$x = 0$ $x = 0$

How do you evaluate log_3 1log31log_3 1?