How do you evaluate ${log}_{3} \sqrt[5]{9}$ $log_3 root5(9)$ ?

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Answer 1 · 2016-02-27T23:18:52

$\frac{2}{5}$ $2/5$

${log}_{3} \sqrt[5]{9} = {log}_{3} \sqrt[5]{3^{2}} = {log}_{3} (3^{\frac{2}{5}})$ $log_3 root(5)9=log_3root(5)(3^2)=log_3(3^(2/5))$

log_a(a^x)=x

So, you will obtain $\frac{2}{5}$ $2/5$

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