How do you evaluate log_5 (132)log5(132)?

1 Answer
Nov 21, 2016

Please see the explanation.

Explanation:

Use a property of all logarithms:

log_5(132) = log_10(132)/log_10(5)log5(132)=log10(132)log10(5)

Every calculator has base 10 logarithms but, if you prefer the natural logarithm:

log_5(132) = ln(132)/ln(5)log5(132)=ln(132)ln(5)

Regardless of which you use, the answer will be the same:

log_5(132) ~~ 3.03 log5(132)3.03