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How do you evaluate ${log}_{8} 1$ $log_8 1$ ?

1 Answer

Jul 8, 2016

0

Explanation:

Let

${log}_{8} 1 = x$ $log_8 1=x$

$\Rightarrow 8^{x} = 1 = 8^{0}$ $=>8^x=1=8^0$

$; . x = 0$ $;.x =0$

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