How do you evaluate ${log 136}^{8} + {log 136}^{17}$ $log136^8+log136^17$ ?

Question

How do you evaluate ${log 136}^{8} + {log 136}^{17}$ $log136^8+log136^17$ ?

1 Answer

Impact of this question

1681 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-12-27T09:13:35

${log 136}^{8} + {log 136}^{17} = 25 log 136 \approx 53.3384727$ $log 136^8+log 136^17 = 25 log 136 ~~ 53.3384727$

Explanation:

If $a > 0$ $a > 0$ then ${log a}^{b} = b log a$ $log a^b = b log a$

So:

${log 136}^{8} + {log 136}^{17} = 8 log 136 + 17 log 136 = 25 log 136$ $log 136^8 + log 136^17 = 8 log 136 + 17 log 136 = 25 log 136$

$\approx 25 \cdot 2.133538908 = 53.3384727$ $~~ 25*2.133538908 = 53.3384727$

Science

Math

Humanities

... and beyond

How do you evaluate ${log 136}^{8} + {log 136}^{17}$ $log136^8+log136^17$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you evaluate log1368+log13617 log136^8+log136^17?

1 Answer

Explanation:

Related questions

Impact of this question

How do you evaluate ${log 136}^{8} + {log 136}^{17}$ $log136^8+log136^17$ ?