How do you evaluate $s^2tdiv10$ for s=-2 and t=-10?

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Answer 1 · 2016-11-28T01:47:45

$-4$

First, rewrite this problem as:

$(s^2t)/10$

Now you can substitute the given values for $s$ and $t$ to evaluate the expression:

$((-2^2)*(-10))/10$

$((-2* -2)*(-10))/10$

$(4*(-10))/10$

$-40/10$

$-4$

How do you evaluate s^2tdiv10s^2tdiv10 for s=-2 and t=-10?