How do you evaluate $sec^-1(sec(-(pi)/6))$ ?

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Answer 1 · 2016-07-11T06:44:06

$-pi/6$

successive operations by a function f and its inverse #f^(-1), either

way, on an operand, returns the operand.

Here, f is $sec$ , $f^(-1)$ is $sec^(-1)$ and the operand is $-pi/6$ ..

So, $sec^(-1) sec (-pi/6)=-pi/6$ .

How do you evaluate sec^-1(sec(-(pi)/6))sec^-1(sec(-(pi)/6))?