How do you evaluate sec(2π)?

1 Answer

Mar 17, 2018

$sec (2 π) = 1$ $sec(2pi)=1$

Explanation:

$sec (2 π)$ $sec(2pi)$ can be written as $sec (0)$ $sec(0)$
because $sec (2 π) = sec (2 π - 0) = sec (0)$ $sec(2pi)= sec(2pi-0)=sec(0)$
and $sec (0) = 1$ $sec(0)=1$
So $sec (2 π) = 1$ $sec(2pi)=1$

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How do you evaluate sec(2π)?

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