Question

How do you evaluate `sec(25pi/6)`?

Answer 1

`sec(25pi/6)=2/sqrt(3)`

Explanation:

`(25pi)/6 = 2xx(2pi)+pi/6`
Each `2pi` represents one complete rotation about the origin.
So
`color(white)("XXX")(25pi)/6=pi/6`

By definition `sec = "hypotenuse"/"adjacent"`

So `sec((25pi)/6)=sec(pi/6)=2/sqrt(3)`