How do you evaluate $sec(60)+csc^2(pi/3)$ ?

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Answer 1 · 2016-08-03T05:52:18

$10/3$

Since $secalpha=1/cosalpha$

and $cscalpha=1/sinalpha$

the given expression becomes:

$1/cos 60+1/sin^2(pi/3)$

Since $cos 60=1/2$ and $sin (pi/3)=sqrt(3)/2$ ,

$2+4/3=10/3$

How do you evaluate sec(60)+csc^2(pi/3)sec(60)+csc^2(pi/3)?