How do you evaluate $sec (- π)$ $sec(-pi)$ ?

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How do you evaluate $sec (- π)$ $sec(-pi)$ ?

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Answer 1 · 2016-08-21T17:22:45

$sec (- π) = \frac{1}{cos (- π)}$ $sec(-pi)=1/cos(-pi)$

Explanation:

The $cos$ $cos$ function is an even function, and that means that $cos (- x) = cos x$ $cos(-x)=cos x$ , for all values of $x$ $x$ . In particular $cos (- π) = cos π = - 1$ $cos(-pi)=cos pi = -1$ . Then, since $sec (- π) = \frac{1}{cos (- π)} = \frac{1}{- 1} = - 1$ $sec (-pi) = 1/cos(-pi)=1/(-1)=-1$

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How do you evaluate $sec (- π)$ $sec(-pi)$ ?

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