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How do you evaluate $sec ({sec}^{- 1} (\sqrt{2}))$ $sec(sec^-1(sqrt2))$ ?

1 Answer

Aug 3, 2016

$= \sqrt{2}$ $=sqrt2$

Explanation:

$sec ({sec}^{- 1} (\sqrt{2}))$ $sec(sec^-1(sqrt2))$
$= \sqrt{2}$ $=sqrt2$

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