How do you evaluate $sin^-1(0)$ ?

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Answer 1 · 2017-01-03T11:50:03

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$sin^-1(0) = x$

Take sin to the left and to the right.

$sin sin^-1 (0) = sin x = 0$

$x = 0 + k pi$ , because $sin k pi = 0$

But what is the domain of $f(x) = sin^-1 x$ ?

Response: $f : [-1, 1] rightarrow [-pi/2, pi/2]$

How do you evaluate sin^-1(0)sin^-1(0)?