How do you evaluate ${sin}^{- 1} (cos (\frac{π}{4}))$ $Sin^-1(cos(pi/4))$ ?

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How do you evaluate ${sin}^{- 1} (cos (\frac{π}{4}))$ $Sin^-1(cos(pi/4))$ ?

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Answer 1 · 2016-03-21T16:19:38

${sin}^{- 1} cos (\frac{π}{4}) = {sin}^{- 1} (\frac{1}{\sqrt{2}}) = {sin}^{- 1} sin (\frac{π}{4}) = \frac{π}{4}$ $sin^-1cos(pi/4)=sin^-1(1/sqrt2)=sin^-1sin(pi/4)=pi/4$

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How do you evaluate ${sin}^{- 1} (cos (\frac{π}{4}))$ $Sin^-1(cos(pi/4))$ ?

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