How do you evaluate $sin^-1(sin (5pi/6))$ ?

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Answer 1 · 2016-04-08T14:52:30

$150^o$

$sin^-1$ and $sin$ cancel each other out. They are opposite functions - its like multiplying and dividing by the same number.

This just leaves $(5pi)/6$ , where $pi$ radians is equal to $180^o$ , in which case

$(5pi)/6 = (5*180^o)/6 = 900^o/6 = 150^o$

How do you evaluate sin^-1(sin (5pi/6))sin^-1(sin (5pi/6))?