Question

How do you evaluate `sin^-1(sin(pi/6))`?

Answer 1

`pi/6`

Explanation:

The following is a pretty good definition for any inverse function:

Let `f(x)` be a function that has an inverse and let `f^-1(x)` be that inverse, then `f^-1(f(x)) = x and f(f^-1(x)) = x`

Therefore, the inverse sine "undoes" what the sine does.