Question

How do you evaluate `sin ((23pi) / 3)`?

Answer 1

`-sqrt3/2`

Explanation:

Trig table and trig unit circle -->
`sin ((23pi)/3) = sin (-pi/3 + (24pi)/3) = sin (-pi/3 + 8pi) =`
`= sin (-pi/3) = - sin (pi/3) = - sqrt3/2`