How do you evaluate $sin (\frac{23 π}{3})$ $sin ((23pi) / 3)$ ?

Question

How do you evaluate $sin (\frac{23 π}{3})$ $sin ((23pi) / 3)$ ?

1 Answer

Impact of this question

8929 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-22T22:09:19

$- \frac{\sqrt{3}}{2}$ $-sqrt3/2$

Explanation:

Trig table and trig unit circle -->
$sin (\frac{23 π}{3}) = sin (- \frac{π}{3} + \frac{24 π}{3}) = sin (- \frac{π}{3} + 8 π) =$ $sin ((23pi)/3) = sin (-pi/3 + (24pi)/3) = sin (-pi/3 + 8pi) =$
$= sin (- \frac{π}{3}) = - sin (\frac{π}{3}) = - \frac{\sqrt{3}}{2}$ $= sin (-pi/3) = - sin (pi/3) = - sqrt3/2$

Science

Math

Humanities

... and beyond

How do you evaluate $sin (\frac{23 π}{3})$ $sin ((23pi) / 3)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you evaluate sin ((23pi) / 3) sin(23π3)sin ((23pi) / 3) ?

1 Answer

Explanation:

Related questions

Impact of this question

How do you evaluate $sin (\frac{23 π}{3})$ $sin ((23pi) / 3)$ ?