How do you evaluate $sin (\frac{- 5 π}{2})$ $sin ((-5pi)/2)$ ?

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How do you evaluate $sin (\frac{- 5 π}{2})$ $sin ((-5pi)/2)$ ?

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Answer 1 · 2016-04-22T17:54:03

$- 1$ $-1$

Explanation:

Use $sin (- x) = - sin x and sin (2 π + x) = sin x$ $sin(-x)=-sinx and sin (2pi+x)=sin x$

Here, $sin (- \frac{5 π}{2}) = - sin (\frac{5 π}{2}) = - sin (2 π + \frac{π}{2}) = - sin (\frac{π}{2}) = - 1$ $sin(-(5pi)/2)=-sin((5pi)/2)=-sin(2pi + pi/2)=-sin (pi/2)=-1$ .

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How do you evaluate $sin (\frac{- 5 π}{2})$ $sin ((-5pi)/2)$ ?

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