How do you evaluate $sin (\frac{7 π}{6})$ $sin ((7pi)/6)$ ?

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How do you evaluate $sin (\frac{7 π}{6})$ $sin ((7pi)/6)$ ?

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Answer 1 · 2016-04-16T02:51:05

$- \frac{1}{2}$ $- 1/2$

Explanation:

Trig unit circle and trig table -->
$sin (\frac{7 π}{6}) = sin (\frac{π}{6} + π) = - sin (\frac{π}{6}) = - \frac{1}{2}$ $sin ((7pi)/6) = sin (pi/6 + pi) = - sin (pi/6) = - 1/2$

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How do you evaluate $sin (\frac{7 π}{6})$ $sin ((7pi)/6)$ ?

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