How do you evaluate $sin ({sin}^{- 1} (\frac{1}{2}))$ $sin(sin^-1(1/2))$ ?

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Answer 1 · 2016-05-04T06:46:45

1/2

Let $a = {sin}^{- 1} (\frac{1}{2})$ $a = sin^(-1)(1/2)$ . Then $sin a = \frac{1}{2}$ $sin a = 1/2$ ..

So, $sin ({sin}^{- 1} \cdot (\frac{1}{2})) = sin a = \frac{1}{2}$ $sin (sin^(-1)*(1/2)) = sin a = 1/2$ .

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