How do you evaluate sine, cosine, tangent of #750^circ# without using a calculator?

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Answer 1 · 2017-10-20T22:18:47

#sin (30)^0 = 1/2#

#cos 30^0 = sqrt3/2#

#tan 30^0 = 1/ sqrt3#

#750^0 = 360^0 + 360^0 + 30^0 = 30^0#

Now you can find the value of #30^0#.

#sin (30)^0 = 1/2#

#cos 30^0 = sqrt3/2#

#tan 30^0 = 1/ sqrt3#