How do you evaluate ${tan}^{- 1} (tan (\frac{2 π}{3}))$ $tan^-1(tan((2pi)/3))$ ?

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Answer 1 · 2017-01-08T19:14:17

The inverse tangent function cancels the tangent function:

${tan}^{- 1} (tan (\frac{2 π}{3})) = \frac{2 π}{3}$ $tan^-1(tan((2pi)/3)) = (2pi)/3$

How do you evaluate tan−1(tan(2π3))tan^-1(tan((2pi)/3))?