Question

How do you evaluate `tan(-(2pi)/3)`?

Answer 1

`tan(-{2pi} /3 ) = sqrt{3}`

Explanation:

Pro tip: Almost every question in trig involves a 30,60,90 triangle or a 45,45,90 triangle.

We know `-{2pi} /3 = -360^circ/3 = -120^circ`

`sin(-120^circ) = - sqrt{3}/2`

`cos(-120^circ) = -1/2`

`tan(-120^circ) = frac{- sqrt{3} /2 }{- 1/2 } = sqrt{3}`