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How do you evaluate $tan 330$ $tan 330$ ?

1 Answer

May 15, 2015

On the trig unit circle:

$tan 330 = tan (- 30 + 360) = - tan 30 = \frac{- s q r 3}{3}$ $tan 330 = tan (-30 + 360) = - tan 30 = ( -sqr3)/3$

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