How do you evaluate $tan (\frac{3 π}{4})$ $Tan((3pi)/4)$ ?

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Answer 1 · 2016-04-25T15:31:55

$tan (\frac{3 π}{4}) = - 1$ $tan((3pi)/4)=-1$

$\frac{3 π}{4} = π - \frac{π}{4}$ $(3pi)/4=pi-pi/4$

$a = π$ $a=pi$

$b = \frac{π}{4}$ $b=pi/4$

$tan (a - b) = \frac{tan a - tan b}{1 + tan a \cdot tan b}$ $tan(a-b)=(tan a-tan b)/(1+tan a*tan b)$

$tan (\frac{3 π}{4}) = \frac{tan π - tan (\frac{π}{4})}{1 + tan π \cdot tan (\frac{π}{4})}$ $tan((3pi)/4)=(tan pi-tan (pi/4))/(1+tan pi*tan (pi/4)$

$tan (\frac{3 π}{4}) = \frac{0 - 1}{1 + 0 \cdot 1}$ $tan((3pi)/4)=(0-1)/(1+0*1)$

$tan (\frac{3 π}{4}) = - \frac{1}{1}$ $tan((3pi)/4)=-1/1$

$tan (\frac{3 π}{4}) = - 1$ $tan((3pi)/4)=-1$

How do you evaluate tan(3π4) Tan((3pi)/4)?