How do you evaluate the expression for $2^{x}$ $2^x$ if $x = - 2$ $x=-2$ and if $x = 3$ $x=3$ ?

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Answer 1 · 2017-01-06T13:17:34

For each of these you substitute the value for $x$ $x$ in the expression.

Problem 1: Solve for $x = - 2$ $x = −2$

$2^{- 2}$ $2^-2$

We can use this rule for exponents to rewrite this problem:

$x^{a} = \frac{1}{x^{- a}}$ $x^color(red)(a) = 1/x^color(red)(-a)$

$2^{- 2}$ $2^color(red)(-2)$

$\frac{1}{2^{- - 2}}$ $1/2^color(red)(- - 2)$

$\frac{1}{2^{2}}$ $1/2^color(red)(2)$

$\frac{1}{4}$ $1/4$

Problem 1: Solve for $x = 3$ $x = 3$

$2^{3}$ $2^3$

$2 \times 2 \times 2$ $2 xx 2 xx 2$

$8$ $8$

How do you evaluate the expression for 2^x2x2^x if x=-2x=−2x=-2 and if x=3x=3x=3?