How do you evaluate the expression r(p+3) + q(p-1),for p=7,q=4,r=3?

1 Answer
Sep 10, 2015

Replace each variable with its value and evaluate arithmetically to get 54

Explanation:

Given color(red)(p=7), color(blue)(q=4), and color(green)(r=3)

color(green)(r)(color(red)(p)+3)+color(blue)(q)(color(red)(p)-1)
color(white)("XXX")becomes
color(green)(3)(color(red)(7)+3)+color(blue)(4)(color(red)(7)-1)

=3(10)+4(6)

=30+24

=54