Question

How do you evaluate the expressions `(2y^2) /( -5y)` given x= 3 and y=5?

Answer 1

There doesn't seem to be a variable `x` in the expression, so let's just ignore that for now. All you have to do is substitute the 2 `y`'s in the expression for `5`.

Explanation:

The expression now looks like this:

`(2(5)^2)/(-5(5))`

Next, solve:

`2(5)^2=50`

`-5*5=-25`

We now have `50/-25`, or `-2`.