How do you evaluate the expressions $\frac{4 x^{4}}{24 x^{3}}$ $(4x^4)/( 24x^3)$ given x= 3 and y=5?

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Answer 1 · 2016-09-06T14:54:31

Plug in 3 for x.

If x=3, then plug that into the expression (was one of the x's supposed to be y?).

$\frac{4 {(3)}^{4}}{24 {(3)}^{3}}$ $(4(3)^4)/(24(3)^3)$

Evaluate the exponents first. In order of operation, exponents come before multiplication.
$3^{4} = 81$ $3^4 = 81$ and $3^{3} = 27$ $3^3= 27$

$\frac{4 (81)}{24 (27)}$ $(4(81))/(24(27))$

$\frac{324}{648} = \frac{1}{2}$ $324/648 = 1/2$

Or, you could first simplify the $\frac{x^{4}}{x^{3}} = x$ $x^4/x^3 = x$

Then the problem becomes $\frac{4 x}{24}$ $(4x)/24$

Plugging in 3 for x:

$\frac{4 (3)}{24} = \frac{12}{24} = \frac{1}{2}$ $(4(3))/24 = 12/24 = 1/2$

However, is it possible you entered the problem incorrectly? We never used y= 5. Was one of the x's supposed to be y?

How do you evaluate the expressions 4x424x3(4x^4)/( 24x^3) given x= 3 and y=5?