How do you evaluate the limit of #lim (x^2+3x-10)/(x^2+5x+6)# as #x->3#?

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Answer 1 · 2016-11-16T17:50:26

#lim_(x->3)(x^2 + 3x - 10)/(x^2 + 5x + 6)#

#=>lim_(x->3)((x + 5)(x -2 ))/((x + 5)(x + 6))#

#=>lim_(x->3) (x- 2)/(x + 6)#

#=> (3- 2)/(3 + 6)#

#=> 1/9#

Hopefully this helps!