How do you evaluate $(u^2- v^2)/(uv)$ for u = 4 and v = 2?

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Answer 1 · 2016-04-24T07:30:23

$1 1/2$

In $(u^2-v^2)/(uv)$ , if $u=4$ and $v=2$

$(u^2-v^2)/(uv)=(4^2-2^2)/(4xx2)=(16-4)/(4xx2)=(3cancel12)/(1cancel4xx2)=3/2=1 1/2$

How do you evaluate (u^2- v^2)/(uv)(u^2- v^2)/(uv) for u = 4 and v = 2?