How do you evaluate $w - 3 x + y$ $w-3x+y$ if w=6, x=0.4, y=1/2, z=-3?

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Answer 1 · 2016-12-23T13:18:09

$4.3$ $color(magenta)(4.3)$

If $w = 6$ $color(red)w=color(red)6$
and $x = 0.4$ $color(blue)x=color(blue)(0.4)$
and $y = \frac{1}{2}$ $color(green)y=color(green)(1/2$

then $w - 3 x + y$ $color(red)w-3color(blue)x+color(green)y$

$XX = 6 - 3 \times (0.4) + \frac{1}{2}$ $color(white)("XX")=color(red)(6)-3 xx (color(blue)0.4) +color(green)(1/2)$

$XX = 5 - 1.2 + 0.5$ $color(white)("XX")=5-1.2+0.5$

$XX = 3.8 + 0.5$ $color(white)("XX")=3.8 +0.5$

$XX = 4.3$ $color(white)("XX")=4.3$

How do you evaluate w-3x+yw−3x+yw-3x+y if w=6, x=0.4, y=1/2, z=-3?