How do you evaluate $x^{2} + 3 x - 5$ $x^2+3x-5$ for x=2?

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Answer 1 · 2016-12-30T01:02:00

$2^{2} + 3 (2) - 5 = 5$ $2^2+3(2)-5=5$

We take the equation:

$x^{2} + 3 x - 5$ $x^2+3x-5$

and substitute 2 for $x$ $x$ :

$2^{2} + 3 (2) - 5$ $2^2+3(2)-5$

$4 + 6 - 5$ $4+6-5$

$5$ $5$

How do you evaluate x^2+3x-5x2+3x−5x^2+3x-5 for x=2?