How do you evaluate x+2y given x=1/2 and y=-2/5?

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How do you evaluate x+2y given x=1/2 and y=-2/5?

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Answer 1 · 2016-11-08T19:10:41

$- \frac{3}{10}$ $-3/10$

Explanation:

Substitute the given numeric values for x and y into the expression.

$\Rightarrow x + 2 y = \frac{1}{2} + (2 \times - \frac{2}{5})$ $rArrx+2y=1/2+(2xx-2/5)$

$= \frac{1}{2} + (- \frac{4}{5}) = \frac{1}{2} - \frac{4}{5}$ $=1/2+(-4/5)=1/2-4/5$

Before subtracting the fractions, we require them to have a common denominator.

$\Rightarrow (\frac{1}{2} \times \frac{5}{5}) - (\frac{4}{5} \times \frac{2}{2}) = \frac{5}{10} - \frac{8}{10} = - \frac{3}{10}$ $rArr(1/2xx5/5)-(4/5xx2/2)=5/10-8/10=-3/10$

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How do you evaluate x+2y given x=1/2 and y=-2/5?

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