How do you evaluate $x^{- 3}$ $x^-3$ for $x = 2$ $x=2$ ?

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How do you evaluate $x^{- 3}$ $x^-3$ for $x = 2$ $x=2$ ?

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Answer 1 · 2018-04-20T14:50:50

$\frac{1}{8}$ $1/8$

Explanation:

$using the law of exponents$ $"using the "color(blue)"law of exponents"$

$∙ x a^{- m} \Leftrightarrow \frac{1}{a^{m}}$ $•color(white)(x)a^-mhArr1/a^m$

$\Rightarrow 2^{- 3} = \frac{1}{2^{3}} = \frac{1}{8}$ $rArr2^-3=1/2^3=1/8$

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How do you evaluate $x^{- 3}$ $x^-3$ for $x = 2$ $x=2$ ?

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